1)a balloon is 21 m above the ground a water is dropped from that height, the bottle accelerate at a uniformaly speed and reaches the ground in 2.1 seconds.
find out the average speed as the bottle falls
i got s=d/t 21/2.1= 10m-1
now it asks show the final velocity is 20m-1 just before it hots the ground.10 points for how do u work out the final velocity of an object before it hits the ground?
And what is your question?10 points for how do u work out the final velocity of an object before it hits the ground?
I think what you got is correct.
Average speed is change in distance over change in time.
= 螖x/螖t
= 21/2.1
= 10 m/s
The question is probably wrong.
What it wants you to do is impossible.
Or maybe I just don't understand the problem well enough.
1) 10ms^-1 10m/s
2) v^2 = u^2 + 2as
v = sqrt (2as)
=sqrt 411.6
= 20.28ms-1
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