If a free falling object falls in 2 seconds at a beginning velocity of 0?

f a free falling object falls in 2 seconds - at a beginning velocity of 0 - what is the final velocity before it touches the ground?If a free falling object falls in 2 seconds at a beginning velocity of 0?
According to Ist Eq of motion





Vf = Vi + at


Vf = Vi + gt (a= acceleration due to gravity)


Putting the values of vi, g and t,


we have


Vf= (0)+ (9.8)(2)


Vf = 19.6 m/s











Hope i helped!If a free falling object falls in 2 seconds at a beginning velocity of 0?
Time(t) = 2 s


Initial velocity(u) = 0


Acceleration(a) due to gravity = 9.8 m/s2


according to the equations of motion,


Final velocity = u +at


=0+9.8 *2


=19.6 m/s2
Acceleration due to gravity is 9.8 m/s^2





This means, that it increases its speed by 9.8 m/s every second.





So in two seconds it's speed will be 19.6 m/s
depends on the size and shape of the object. Real life or in a vacume?