An object of mass 2.00 kg is held at a position A, a vertical height of 20.0 m above the ground. Point B is 8.00 m directly below A. Neglect air resistance and use g = 10.0 m/s2 (to the second power)What is the ratio of the total energy of the object at position A to position B?
If there is no air resistance, by the conservation of energy - the energies will be the same at A only has PE; at B has combination of PE + gained KE.What is the ratio of the total energy of the object at position A to position B?
if you are talking about potential energy difference , it is
mgh1 / mgh2 = h1/h2 = 20/12 = 5:3
if you are talking about a freefall from 20 m to 12 m , the the ratio remains 1 as the potential energy is reduced but corresponding Kinetic energy is gained .
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