Such surfaces absorb energy by getting deformed (though they may regain some of the deformation later). Hence the collision does not remain strictly elastic, hence momentum (m*v) decreases as the total energy (1/2 mv^2) has decreased, resulting in lessor damages..The change in momentum of a colliding object is the same whether the surface is padded or not?
F x delta t = m x delta v
=%26gt;if m x delta v is constant in both the conditions,then:-
=%26gt;F x delta t = constant
=%26gt;in padded:- delta t is more thus F is less
=%26gt;in unpadded:- delta t is less thus F is more
Then in padded condition P = F/A will be less = less damage
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