The other answer is right...no such thing...but...what if? Let's look at this for fun...and maybe a bit of physics.
First, the unstoppable force F = d(mv)/dt = dm/dt v + m dv/dt; assuming it's some mass m that slams at velocity v into the immovable object M. dm/dt is the change in mass over time and dv/dt is the change in its velocity over time.
Second, the immovable object F = dM/dt V + M dV/dt; where the force F is the same one as for the unstoppable object, but in the opposite direction. This is the equal, but opposite force law of Newton.
Thus dm/dt v + m dv/dt = dM/dt V + M dV/dt; so that dm v + m dv = dM V + M dV holds when the 1/dt factors are removed from both sides of the equation. This simply means, whatever happens, happens to both M and m in the same elapsed time dt. So, let's see what happens in that dt timeframe.
dm v + m dv = dM V + M dV when the force and force reaction are equal, but opposite. Looking at the left-most terms on both sides of the = will there be a change in mass dm or dM?
There will be if we go atomic from the pressure resulting from the collision. (This is the kind of energy that causes the fusion reactions on our Sun for example.) If this happens or not would, of course, depend on how much kinetic energy the mass m had to convert into pressure upon impact.
In any case, E = dm c^2 would be the amount of energy released if dm mass is lost by the impact. For example, if dm = 1 kg of mass lost, then E = 9X10^16 Newton meters of energy created from the lost mass upon impact. And since the immovable object is subjected to the same kinetic energy (force), it, too, would undergo a mass change.
So the total energy released would be twice E or about 18X10^16 Newton meters per kg of the M and m. To put this into perspective, this is over 66 million megtons of energy released from the combined loss 1 kg of m and 1 kg of M. That is, it would be like 66 million one megaton nuclear bombs exploding at the same time. But only if there was a change in mass dm and dM.
So what if dm = dM = 0? There is no nuclear reaction because the two masses do not change at this point. Then from dm v + m dv = dM V + M dV, we have m dv = M dV; where dv = 0 and dV = 0. That is, the mass m velocity continues on (unstoppable), while the mass M velocity remains fixed at zero (immovable). Consequently, both velocities are constant, but v %26gt; 0 constant and V = 0 constant from the unstoppable and immovable assumptions. Therefore their changes are both zero.
Then m dv = m 0 = M 0 = M dV. And we have the interesting result that 0 = 0 if v = constant %26gt; 0 and V = 0. This is, of course, a meaningless result because there are no clues what would happen to the masses m and M. So let's just change the assumptions a bit.
If v is allowed to slow, but plod ahead...not totally stopped in other words, we have m (-dv) = M 0 = 0. The minus sign in -dv signifies a slowing down. Thus - mdv = 0, which gives the very interesting result that, since dv %26lt;%26gt; 0, mass m must be zero. Therefore, m - dm = 0 and all the mass m must once again be converted into energy E = dm c^2 = mc^2. Again millions of nuclear weapons are going off at once.
So there we have it. Fundamentally, some or all the mass of the unstoppable mass with F = dm/dt v + m dv/dt force and of the immovable object M must be converted to energy via the E = dm c^2 and E = dM c^2 relationships. And, the energy levels released are staggering, even for a mass as small as 1 kg.What happens when an unstoppable force hits an unmovable object?
unstoppable and unmovable are terms that defy laws of physics
if there are forces that are true then there would be a whole new set of laws ...
The only experience I've ever had on this point was when I met a fantastic lady. We got married.
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